Question

a/b+b/c=1 then find a³+b³
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Answer 1

Answer:

Step-by-step explanation:

a/b + b/a = 1

=> making denominator equal

=> (a²+b²)/ab = 1

=> a²+b² = ab

we know that , a³+b³ = (a+b)(a²+b²-ab)

=> a³+b³= (a+b)(ab-ab)

(as , a²+b² = ab)

=> a³+ b³ = (a+b)(0) = 0

the answer is 0

Answer 2

Answer:

Step-by-step explanation:

a/b + b/a = 1

=> making denominator equal

=> (a²+b²)/ab = 1

=> a²+b² = ab

we know that , a³+b³ = (a+b)(a²+b²-ab)

=> a³+b³= (a+b)(ab-ab)

(as , a²+b² = ab)

=> a³+ b³ = (a+b)(0) = 0

the answer is 0