Question

(a-b) (b-c)+(b-c) (c-a)+(c-a) (a-b)​

Answer 1

Answer:

-b²-c²-b²+2ab-ba-bc+ac

Step-by-step explanation:

(a-b) (b-c)+(b-c) (c-a)+(c-a) (a-b)

a(b-c)-b(b-c)+b(c-a)-c(c-a)+c(a-b)-a(a-b)

ab-ac-b²-bc+bc-ba-c²+ac+ac-bc-a²+ab

-b²-c²-b²+2ab-ba-bc+ac

JAI SHREE KRISHNA

Answer 2

$\huge{\underline{\underline{\purple{♡Solution→}}}}$

$(a - b)(b - c) + (b - c)(c - a) + (c - a)(a - b)$

$= ab - ac - {b}^{2} + bc + bc - ab - {c}^{2} + ac + ac - bc - {a}^{2} + ab \: \\ = ab - ab + ab - ac + ac + ac + bc + bc - bc - {b}^{2} - {c}^{2} - {a}^{2} \\ = ab + ac + bc - {b}^{2} - {c}^{2} - {a}^{2}$

$= - {a}^{2} - {b}^{2} - {c}^{2} + ab + bc + ca$

Mark as Brainliest !! ✨✨