a+b,b+C,C+A can complete a work un 10,12,20 days respectively. in how much they alone do the work.
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Answer:
a = 30 days . b= 15 days. c = 60 days
Step-by-step explanation:
take LCM of 10, 12 ,20 i.e 60.. so we assume total units of work as 60
so per day a+b does 6 units of work. ( 60 / 10)
b+c = 5 units of work ( 60/ 12)
c+ a = 3 units of work.(60/20)
total a + b + c does 7 units of work daily. ( 6+5+3)/2
a alone does. 2 units ( 7-5)
b alone does 4 units
c alone does 1 unit of work.
hence a takes 30 days. (60/2)
b takes 15 days
c takes 60 days
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