A/B=B/C=C/D --
B³+C³+D³/A³+C³+B³=?
Any one answr this qsn with explain frnds
Answers
Answered by
2
hey mate
here is your answer
a/b=b/c=c/a=k(let)
a=bk. b=ck. c=ak
thus
b³+c³+d³/a³+b³+c
b³+c³+d³/(bk)³+(ck)³+(ak)³
b³+c³+d³/k³(b³+c³+d³)
1/k³
1/(each ratio)³ (answer)
here is your answer
a/b=b/c=c/a=k(let)
a=bk. b=ck. c=ak
thus
b³+c³+d³/a³+b³+c
b³+c³+d³/(bk)³+(ck)³+(ak)³
b³+c³+d³/k³(b³+c³+d³)
1/k³
1/(each ratio)³ (answer)
Similar questions