Question

a b
_ - _
b c

The values are a=3,b=2,c= -1
Please answer​

Answer 1

Answer:

3(a2+b2+c2)=(a2+b2+c2)+2(ab+bc+ca)

⇒ 2a2+2b2+2c2-2ab-2bc-2ac=0

⇒ (a-b)2 + (b-c)2 + (c-a)2 =0

⇒ a=b=c