Question

A B = BC, angleA = angle C and angleABD=angle CBE prove that CD = AE

Answer 1

Answer:

In the figure, AB = BC, ∠A = ∠C and ∠ABD = ∠CBE. Prove that CD = AE.

Sol. We have,∠ABD = ∠CBE   [Given]

Adding ∠DBE both sides, we get∠ABD + ∠DBE = ∠CBE + ∠DBE ⇒∠ABE = ∠CBD

Now, in ΔABE and ΔCBD,

∠BAE = ∠BCD[Given]

  AB = BC[Given]

∠ABE = ∠CBD[Proved above]

∴By ASA congruency, ΔABE ≅ΔCBD

Hence, by CPCT, CD = AE     Proved.

Answer 2

I don't know I'm sorry