a+b+c=0 find a²/ab+b²/ca+c²/bc
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Given a + b + c = 0
⇒ a3 + b3 + c3 = 3abc → (1)
Consider, (a2/bc) + (b2/ca) + (c2/ab)
= (a3 + b3 + c3)/abc
= 3abc/abc = 3 [From (1)]..
⇒ a3 + b3 + c3 = 3abc → (1)
Consider, (a2/bc) + (b2/ca) + (c2/ab)
= (a3 + b3 + c3)/abc
= 3abc/abc = 3 [From (1)]..
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