Question

√a+√b+√c=0 ,find the value of (a+b-c)^2

Answer 1

Answer:

√a+√b-√c=0

or, √a+√b=√c

Squaring both sides,

(√a)²+2√a√b+(√b)²=(√c)²

or, a+b+2√ab=c

or, a+b-c=-2√ab

Again squaring both sides,

(a+b-c)²=(-2√ab)²

or, (a+b-c)²=4ab

∴, The answer is c)4ab

Answer 2

Step-by-step explanation:

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