Question

a+b+c=0,now proved that (a^2,bc),(b^2,ca),(c^2,ab) these point are in one line.​

Answer 1

Step-by-step explanation:

for these to be in straight line :

slope of line should be equal.

slope of line formed by first 2 points = (ca-bc)/(b^2-a^2)=

= c*(a-b)/((b-a)*(b+a))= c/-(a+b)= c/-(-c) =-1 (because a+b+c=0)

similarly sloe of line formed by other 2 points = (ab-ca)/(c^2-b^2)= a*(b-c)/((b+c)*(c-b) = a/-a=-1

since slope of line is same in both cases, all 3 points lie on the same line.