A+b+c=0 prove a2/bc+b2/ca+c2/ab=3
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Step-by-step explanation:
a^2/bc +b^2/ca + c^2/ab =3
lcm of ab,bc,ca=abc
(a^2*a+b^2*b+c^2*c)=3abc
a^3+b^3+c^3=3abc
a^3+b^3+c^3-3abc=0
- but a^3+b^3+c^3-3abc=(a+b+c)*(a^2+b^2+c^2-ab-bc-ca)
- a+b+c=0 given
- (0)*(a^2+b^2+c^2-ab-bc-ca)=0
something multiplied by 0 is equals to 0
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