Question

a+b+c=0 then (A3+b3+c3)​

Answer 1

Now,

a3+b3 + c3 = (a+ b + c) (a2 + b2 + c2 – ab – be – ca) + 3abc

[using identity, a3+b3 + c3 – 3 abc = (a + b + c)(a2+b2+c2 –ab–bc-ca)] = 0 + 3abc [∴ a + b + c = 0]

a3+b3 + c3 = 3abc.

Answer 2

Answer:

in easy method a +b+c =0 a3 +a3+a3 =a as common 3 as common ans a3

Step-by-step explanation:

a3 -a3 =0+a3 =a3