Question

a+b+c=0 then show that a^3+b^3+c^3=3abc

Answer 1

We know a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ac). .
This if a+b+c. Is. Then the whole RHS will be 0. This
a³+b³+c³-3abc=0

a³+b³+c³=3abc