Math, asked by memanvisikka308, 10 months ago

a+b+c=0 then show that a2/bc+b2/ca+c2/ab=3

Answers

Answered by mysticd

Solution :

It is given that ,

a + b + c = 0 ----( 1 )

a³ + b³ + c³ = 3abc ----( 2 )

LHS = a²/bc + b²/ac + c²/ab

= ( a³ + b³ + c³ )/abc

= 3abc/abc [ from ( 1 ) ]

= 3

= RHS

••••

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