a+b+c = 10 and (ab+bc+CA)= 32. then find(a3+b3+c3-3abc)
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a+b+c = 32 not 36
ab + bc+ ca = 32 not 36
ab + bc + ca = 32 not 36
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a + b + c = 10
ab + bc + ca = 32
(a+b+c)^2 = a2+b2+c2 +2 (ab + bc + ca)
(10)^2 = a2+b2+c2+2(32)
36 = a^2+ b^2+ c^2
a3 + b3 + c3 - 3abc = (a+b+c) (a2+b2+c2-ab-bc-ca)
= (10) (36-32) = 40
wrong answer
yep it is right
He has written ab+bc+ca = 36 but it is 32
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