Math, asked by aasthagarg4409, 1 year ago

a+b+c=11 and ab+bc+ca=20 find a3+b3+c3-3ab

Answers

Answered by sumith4

0

a=1
b=1
c=9
1×3+1×9+9×3-3×1×1
3+9+27-3
36
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