a+b+c=13 and a²+b²+c²=69 find ab+bc+ca= ?
samikshas269:
ur answer is 50
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a+b+c=13 and a²+b²+c²=69
(a + b + c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca)
2(ab + bc + ca) = (a + b + c)^2 - (a^2 + b^2 + c^2) = 169 - 69 = 100.
(ab + bc + ca) = 50.
(a + b + c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca)
2(ab + bc + ca) = (a + b + c)^2 - (a^2 + b^2 + c^2) = 169 - 69 = 100.
(ab + bc + ca) = 50.
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