Question

(a+b+c)=14 , (a^2+b^2+c^2) = 74 (ab+bc+ca) = ?​

Answer 1

Answer:

a^2+b^2+c^2+2(ab+BC+AC)=0

74+2(ab+BC+CA)=0

ab+BC+ca= -74/2= -37

Answer 2

Answer:

61

Step-by-step explanation:

a+b+c=14

(a^2+b^2+c^2)=74

(a+b+c)^2=196

using identity (a+b+c)^2= (a^2+b^2+c^2) +2(ab+bc+ca)

∴196=74+2(ab+bc+ca)

∴98=37+ab+bc+ca)

∴98-37=(ab+bc+ca)

∴61=ab+bc+ca