Question

a(b+c) = 152
b(c+a) = 162
c(a+b) = 110
Then find the value of abc

Answer 1

Add all the three equations:    2 (ab+bc+ ca) = 152+162+110 = 424

So   ab + bc + ca = 212    -- (10)

(10) - (1) :  bc = 60

(10) - (2) :  ac = 50

(10) - (3) :  ab = 102

So  abc)² = 60 *50*102

       abc = 60* √85