A+B+C=180°=cos2A+cos2B+cos2C=
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=cos2(A+B+C)
=cos2(180°) ________{A+B+C=180°}
=cos360°
=1 ________{cos360°=1}
=cos2(180°) ________{A+B+C=180°}
=cos360°
=1 ________{cos360°=1}
Answered by
0
=cos2A+cos2B+cos2C
=cos2(A+B+C)
=cos2(180°) ________{A+B+C=180°}
=cos360°
=1 ________{cos360°=1}
=cos2(A+B+C)
=cos2(180°) ________{A+B+C=180°}
=cos360°
=1 ________{cos360°=1}
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