(a+b+c)2 + (a-b-c) ²
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0
Answer:
just open the identity...
Answered by
16
Answer:
................❤
Using formula, u can solve it easily.
(a + b +c) ^2 + ( a - b -c) ^2
= a^2 + b^2 +c^2 + 2ab +2bc + 2ca + a^2 + b^2 + c^2 -2ab + 2bc -2ca
= 3a^2 + 3b^2 + 3c^2 +4ab
Hope it’s helpful....... ☺
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