Question

(a+b+c)^2-(a-b-c)^2+4b^2-4c^2

Answer 1

☆Hello friend☆

( a+b+c )^2 - ( a-b-c )^2 + 4b^2 - 4c^2

(a+b+c+ a-b-c)(a+b+c-a+b+c) + (2b)^2 - (2c)^2

2a(2b+2c) +(2b-2c)(2b+2c)

Hope it helps☺

Answer 2

Consider, (a+b+c)2 – (a – b – c)2+ 4b2– 4c2
= a2 + b2 + c2 + 2ab + 2bc + 2ca – (a2 + b2 + c2 – 2ab + 2bc – 2ca)+ 4b2– 4c2
= a2 + b2 + c2 + 2ab + 2bc + 2ca – a2 – b2 – c2 + 2ab – 2bc +2ca + 4b2– 4c2
= 4ab + 4ca + 4b2– 4c2
= 4(ab + ca + b2– c2)
= 4[a(b + c) +(b2– c2)]
= 4[a(b + c) + (b + c)(b – c)]
= 4(b + c)(a + b – c)