Math, asked by manasvihp21, 1 year ago

(a+b-c)^2+ (a-b+c)^2

Answers

Answered by deekshantsinghal7996
2

(a + b  - c)  {}^{2}  + (a - b + c) { }^{2}   \\ a {}^{2}  + b {}^{2}  + c {}^{2}    +   2ab  -  2bc  - 2ca  +  a {}^{2}  + b {}^{2}  + c {}^{2}  - 2ab - 2bc + 2ca \\ 2 {a}^{2}  + 2 {b}^{2}  + 2 {c}^{2}  - 4bc

manasvihp21: is that a identity?
manasvihp21: how did you get 2a^2
deekshantsinghal7996: Yes it is done by using the identity a^2 +b^2+c^2+2ab+2bc+2ca
deekshantsinghal7996: as we can see in ans there are a2 +--- + a2 therefore it becomes 2a^2
manasvihp21: ok .. thanks a lot :)
deekshantsinghal7996: Its my pleasure
Answered by masterman12
0
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