Question

A+b+c=4root3 and a2+b2+c2=16 then the ratio a:b:c is - meritnation

Answer 1

Answer:

Step-by-step explanation:

we are given that $a+b+c=4\sqrt{3}$ and $a^2+b^2+c^2=16$.

Now, using the identity, we get

$(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca$

On substituting the values, we get

$48=16+2(ab+bc+ca)$

$32=2(ab+bc+ca)$

$ab+bc+ca=16$

Now, comparing the above equation with  $a^2+b^2+c^2=16$, we get

$a^2=ab$⇒$\frac{a}{b}=1$⇒$a:b=1$

Also, $b^2=bc$⇒$\frac{b}{c}=1$⇒$b:c=1$

and $c^2=ca$⇒$\frac{c}{a}=1$⇒$c:a=1$

Therefore, the required ratios is:

a:b:c=1:1:1

Answer 2

Answer:

Step-by-step explanation: