Question

a+b+c=5,ab+bc+ca =1 then a^2 +b^2+

Answer 1

Step-by-step explanation:

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Answer 2

$\sf{given \: \: a + b + c = 5}$

$\rm{squaring\: on \:both \:sides}$

$\sf{(a + b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2(ab + bc + ca)$

$\sf{(5)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2(1)$

$\sf{25 = {a}^{2} + {b}^{2} + {c}^{2} + 2}$

$\sf{ {a}^{2} + {b}^{2} + {c}^{2} = 25 - 2}$

$\fbox{\sf{ {a}^{2} + {b}^{2} + {c}^{2} = 23}}$