out of a certain sum of money a boy spends 3/5,and then 1/4of the remainder.He has ₹15 left .How much amount had he at first?
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I thought 49 rupees should be the answer.
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Answer : Rs. 50
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Solution :
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Let, a boy has Rs. X
Then, given that : Boy spends 3/5,and then 1/4of the remainder and then he has Rs. left
According to the question :
X × (1-3/5)×(1-1/4) = 15
=> X × 2/5 × 3/4 = 15
=> X = (15×5×4)/(2×3)
=> X = 50
So, he had Rs. 50 total at first.
awesomeme10917:
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