a+b-c=5 and a^2+b^2+c^2=29 find the value of ab -bc-ca
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Hey brain-ly user is answer is here.....
Given:-
a+b-c=5........(i)
squaring of eq......(i)
(a+b-c)^2=a^2+b^2+c^2+2(ab-bc-ca)
(5)^2=29+2(ab-bc-ca)
25=29+2(ab-bc-ca)
-4=2(ab-bc-ca)
[[[[[[ab-bc-ca=-2]]]]]]
Please mark me as brainliest.....
Given:-
a+b-c=5........(i)
squaring of eq......(i)
(a+b-c)^2=a^2+b^2+c^2+2(ab-bc-ca)
(5)^2=29+2(ab-bc-ca)
25=29+2(ab-bc-ca)
-4=2(ab-bc-ca)
[[[[[[ab-bc-ca=-2]]]]]]
Please mark me as brainliest.....
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