Math, asked by rahul9385, 1 year ago

a+b-c=5 and a^2+b^2+c^2=29 find the value of ab -bc-ca

Answers

Answered by gangwarakash999
4
Hey brain-ly user is answer is here.....

Given:-

a+b-c=5........(i)

squaring of eq......(i)

(a+b-c)^2=a^2+b^2+c^2+2(ab-bc-ca)

(5)^2=29+2(ab-bc-ca)

25=29+2(ab-bc-ca)

-4=2(ab-bc-ca)

[[[[[[ab-bc-ca=-2]]]]]]

Please mark me as brainliest.....
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