A+b+c=5 nad ab+bc+ca=10 , then find the value of a3+b3+c3-3abc
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a3 + b3 + c3 - 3abc
= (a + b + c) {(a + b + c)2 - 3(ab + bc + ca)}
= 5 × (5^2 - 3×10)
= 5 × (25 - 30)
= 5 × (-5)
= -25.
# I hope that this will help you.
a3 + b3 + c3 - 3abc
= (a + b + c) {(a + b + c)2 - 3(ab + bc + ca)}
= 5 × (5^2 - 3×10)
= 5 × (25 - 30)
= 5 × (-5)
= -25.
# I hope that this will help you.
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