a+b+c=9 ab+bc+ca=26 A2+B2+c2
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Answered by
2
Hey mate !!
Here's your answer :))
(a+b+c)^2 = a^2 + b^2 + c^2 + 2(ab+bc+ca)
9^2 = a^2+b^2+c^2+2*26
81=a^2+b^2+c^2+54
81-54=a^2+b^2+c^2
27 => a^2+b^2+c^2
Hope this helps☺☺
Here's your answer :))
(a+b+c)^2 = a^2 + b^2 + c^2 + 2(ab+bc+ca)
9^2 = a^2+b^2+c^2+2*26
81=a^2+b^2+c^2+54
81-54=a^2+b^2+c^2
27 => a^2+b^2+c^2
Hope this helps☺☺
kirwnkumar:
thanks man
Answered by
1
Answer:
29
Step-by-step explanation:
(a+b+c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
(9)2= a2 +b2 +c2 + 2 (ab+bc+ca)
81=a2+b2+c2+2(26)
81= a2+b2+c2+52
81-52 = a2+b2+c2
29= a2+b2+c2
hope it helps
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