a+b+c=9 and ab+bc+ac=26,find a^2 +b^2 +c^2
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Hey !!
Answer:
( a + b + c ) ^ 2 = a^2 + b^2 + c^2 + 2 ( ab + bc + ca )
Substituting the value , we get :-
9^2 = a^2 + b^2 + c^2 + 2 x 26
81 = a^2 + b^2 + c^2 + 52
81 - 52 = a^2 + b^2 + c^2
29 = a^2 + b^2 + c^2
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