Math, asked by jasmeh07, 6 months ago

(a+b+c) (a+b-c) + 3a(2b+5c) = 0

Answers

Answered by class7ssanjanadws
1

Answer:

(3+2+5) (3+2-5)

Step-by-step explanation:

3+2+5 is converted to

(3+2-5). a=3

if we - 2 and 5 we get -3. b=2

so, 3+(-3). c=5

+ of - gives -

3-3 = 0

.: Ans is 0 only

Answered by karansshettyk
1

Answer:

abc + abc+6ab+15ac=0

abc square+6ab+15ac=0

abc square+21 a sq bc=0

=21 a cube b sq c sq=0

=21 a^4 b^3 c^3=0

=[ since we are dividing by 0 the answer will be 0 it self]

MARK AS BRAINLIEST

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