(a+b+c) (a+b-c) + 3a(2b+5c) = 0
Answers
Answered by
1
Answer:
(3+2+5) (3+2-5)
Step-by-step explanation:
3+2+5 is converted to
(3+2-5). a=3
if we - 2 and 5 we get -3. b=2
so, 3+(-3). c=5
+ of - gives -
3-3 = 0
.: Ans is 0 only
Answered by
1
Answer:
abc + abc+6ab+15ac=0
abc square+6ab+15ac=0
abc square+21 a sq bc=0
=21 a cube b sq c sq=0
=21 a^4 b^3 c^3=0
=[ since we are dividing by 0 the answer will be 0 it self]
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