Question

(
a+b-c-a-b+c.-a+b+ Find the
b) a, b, care positive real numbers. Such that
b
a
(a + b)(b + c)(c + a)
value of
abc​

Answer 1

Answer:

8

Step-by-step explanation:

a+b-c/c =a-b+c/b

b(a+b-c)=c(a-b+c)

ab+b^2-bc=ac-bc+c^2

ab-ac+b^2-c^2=0

a(b-c)+(b+c)(b-c)=0

(b-c)(a+b+c)=0

=> b-c=0

=> b=c

Similarly c=a

therefore a=b=c

(a+b)(b+c)(c+a)/abc=(a+a)(b+b)(c+c)/abc

2a.2b.2c/abc =8abc/abc

                   =8

HOPE IT WILL HELP YOU....