Question

A body is released from a height of 5 m. If friction is
ignored then its velocity Just before striking the ground
will be (g = 10 ms):
A) 5 m/s
C) 15 m/s
B) 16 m/s
D) 20 m/s​

Answer 1

Explanation:

${v}^{2} - {u}^{2} = 2as$

u=0,because it is released from hight

v=√{(2×10×5)+0}. (take a=g=10)

=√(100)

=10m/sec