A, B, C and D are four point on a hemispherical cup placed inverted on the ground. Diameter BC = 50 cm. A 250 g particle at rest at A, slide down along the smooth surface of the cup. Calculate it’s (a) Potential energy at A relative to B.(b) Speed at the point B (Lowest point).(c) Kinetic and potential energy at D.
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The altitude of point A (top point of hemispherical cup) : relative to B.
= radius = 25 cm
PE = m g h = 0.250 kg * 10 m/sec^2 * 0.25m = 0.625 J
speed at B: v m/s
KE at B = PE at A --- energy conservation.
1/2 m v^2 = 0.625 J
v = 5 √2 m/s
It is not clear where the point D is ....
If we know the height at point D, then we can calculate PE and then find the KE by 0.625 J - PE.
= radius = 25 cm
PE = m g h = 0.250 kg * 10 m/sec^2 * 0.25m = 0.625 J
speed at B: v m/s
KE at B = PE at A --- energy conservation.
1/2 m v^2 = 0.625 J
v = 5 √2 m/s
It is not clear where the point D is ....
If we know the height at point D, then we can calculate PE and then find the KE by 0.625 J - PE.
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