a b c and d are in GP show that a square b + b square + c square bracket close b square + c square + b square bracket close is equal to a b + BC + CD square
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dasddasd
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If a,b,c,d are in G.P ,then prove that-
(a-b)^2 , (b-c)^2 , (c-d)^2 are in G.P
^^ This is the answer, actually I solved it in my notebook and I am PC right now, so couldn't click the pic of explantation sorry. But that's the right answer for sure.
Step-by-step explanation:
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