Find the volume, the total surface area, the lateral surface area and the diagonal of a cube each
of whose edges measures :
(i) 8 m
(ii) 6.5 cm
(iii) 2 cm 6 mm
(Take 3 = 1.73 in each case)
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Answer:
Edge of cube = 9 m
<b>Volume of cube =</b>
{edge}^{3}
= {9}^{3}
= 729
<b><u> so, volume of cube =729 m^3</b></u>
<b>2.Lateral surface area of cube = 4× edge^2</b>
= 4 \times {9}^{2}
= 4 \times 81
= 324 {m}^{2}
<b><u>So, Lateral Surface Area of cube = 324 m^2</b></u>
<b>3.Total surface area of cube = 6×edge^2</b>
= 6 \times {9}^{2}
= 6 \times 81
= 486 \: m {}^{2}
<b><u>So, Total Surface Area of cube = 486 m^2</b></u>
<b>Diagonal of the cube =</b>
\sqrt{edge {}^{2} + {edge}^{2} + {edge}^{2} }
= \sqrt{3 \: {edge}^{2} }
= edge \sqrt{3}
= 9 \sqrt{3}
= 9 \times 1.73
= 15.57 \: m
<b><u>So, diagonal of cube=15.57 m </b></u>
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Warm regards
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