Question

A, B, C and D are points on a circle with centre O. AC and BD intersect at point

M such that

∠ = 75° , ∠ = 35°, find ∠BCA​

Answer 1

Answer:

Hope it helps..

Step-by-step explanation:

Here, ∠BEC+∠DEC=180

∘

(Linear pairs are complimentary)

⟹ 130

∘

+∠DEC=180

∘

⟹ ∠DEC=50

∘

.

In ΔDEC,

∠DEC+∠ECD+∠CDE=180

∘

...(Angle sum property)

⟹ 50

o

+20

o

+∠CDE=180

∘

⟹ ∠CDE=110

∘

.

By theorem of circles,

∠BAC=∠CDB

⟹ ∠BAC=∠CDE=110

o

∴∠BAC=110

∘

.

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