Question

A, B, C and D are the four points on a circle. AC and BD intersect at point E such that BEC = 130° and ECD = 20°. Find BAC.

Answer 1

∠EDC+∠CDE=130°
∠EDC=130°-20°
∠EDC=110°
 Now,
∠EDC=∠BAC=110°

Answer 2

Hello mate =_=

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Solution:

∠BEC+∠DEC=180°                (Linear Pair)

⇒∠130°+∠DEC=180°

⇒∠DEC=180°−130°=50°             ......(1)

∠DEC+∠DCE+∠BDC=180°

Putting value of ∠DCE and using (1), we get

50°+20°+∠BDC=180°

⇒∠BDC=180°−50°−20°=110°    

We also have ∠BDC=∠BAC  (Angles in the same segment are equal.)

⇒∠BAC=110°

hope, this will help you.

Thank you______❤

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