Question

A,B,C and D are the four points on the circle AC and BD intersect at a point such that angle BAC is equal to 130° and Angle BCD is equal to 20° find angle BAC.

Answer 1

Thus, the angle BAC = 110°

...HOPE YOU GOT IT...

Answer 2

HERE IS YOUR ANSWER :-

A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠∠ BEC = 130∘130∘ and ∠∠ECD = 20∘20∘. Then, ∠∠ BAC is equal to  


A) 90∘90∘

B) 100∘100∘

C) 110∘110∘

D) 120∘120∘


Correct Answer:

C) 110∘110∘


Description for Correct answer:

∠CED=180∘−130∘=50∘∠CED=180∘−130∘=50∘

Now, in △CED△CED

∠ECD+∠CED+∠CDE=180∘∠ECD+∠CED+∠CDE=180∘

=> ∠CDE=180∘−50∘−20∘=110∘∠CDE=180∘−50∘−20∘=110∘

∴∠BAC=∠CDE=110∘∴∠BAC=∠CDE=110∘

[angles in same segment are equal]

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