A, B, C, and D play a game of cards. A says to B If I give you 8 cards, you will have as many as C has and I shall have 3 less than what C has. Also if I take 6 cards from C, I shall have twice as many as D has. If B and D together have 50 cards, how many cards have A got?
Answers
Answered by
0
Step-by-step explanation:
ANSWER
As per the question.
B−3=E....(1)
B+3=D...(2)
A+B=D+E+10 ...(3)
B=C+2...(4)
A+B+C+D+E=133 ...(5)
From 1 and 2
B−E=D−B
2B=D+E ..(6)
From 3 and 6
A+B=2B+10
B=A−10
A=B+10...(7)
From 5 6 7 and 4
B+10+B+B−2+2B=133
∴B=25
Answered by
5
Answer:
If we read given question carefully, we get,
B + 8 = C ---(i)
A - 8 = C-3 ---(ii)
A + 6 = 2D ---(iii)
B + D = 50 ---(iv)
Putting C = A -5 from (ii) into (i), we have :
B+8 = A-5 or A-B = 13 ---(v)
Putting D = 50-B from (iv) and (iii), we have :
A+6 = 100-2B or A+2B = 94 ---(vi)
Solving (v) and (vi), we get
B = 27 and A = 40
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