Math, asked by xiaodejundejun, 10 hours ago

A, B, C are mutually exclusive and exhaustive events of a random experiments. If P(B) = (3/2) P(A) , and P(C) = (1/2) P(B) , find P(A)​

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Answered by aldomicheal30
0

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A, B, C are three mutually exclusive and exhaustive events associated with a random experiment. Find P(A), it being given that P(B)=

2

3

P(A) and P(C)=

2

1

P(B).

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Answer

Correct option is

C

13

4

Let P(A)=p. Then,

P(B)=

2

3

P(A)⟹P(B)=

2

3

p and P(C)=

2

1

P(B)⟹P(C)=

4

3

p

Since A, B, C are mutually exclusive and exhaustive events associated with a random experiment.

A∪B∪C=S

P(A∪B∪C)=P(S)

P(A∪B∪C)=1

P(A)+P(B)+P(C)=1

p+

2

3

p+

4

3

p=1

p=

13

4

P(A)=

13

4

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