A, B, C are mutually exclusive and exhaustive events of a random experiments. If P(B) = (3/2) P(A) , and P(C) = (1/2) P(B) , find P(A)
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A, B, C are three mutually exclusive and exhaustive events associated with a random experiment. Find P(A), it being given that P(B)=
2
3
P(A) and P(C)=
2
1
P(B).
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Answer
Correct option is
C
13
4
Let P(A)=p. Then,
P(B)=
2
3
P(A)⟹P(B)=
2
3
p and P(C)=
2
1
P(B)⟹P(C)=
4
3
p
Since A, B, C are mutually exclusive and exhaustive events associated with a random experiment.
A∪B∪C=S
P(A∪B∪C)=P(S)
P(A∪B∪C)=1
P(A)+P(B)+P(C)=1
p+
2
3
p+
4
3
p=1
p=
13
4
P(A)=
13
4
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