Math, asked by SaKriHa, 9 months ago

A,B,C are the zeros of x^3-2x^2-2x+1=0,then A^2+B^2+C^2=?​

Answers

Answered by Anonymous
1

Step-by-step explanation:

According to my view ,

A + B + C = 2/1 = 2

AB + BC + CA = -2

A² + B² + C² = (A+B+C)² - 2(AB+BC+CA)

= (2)² - 2(-2)

= 4 + 4 = 8

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