A,B,C are the zeros of x^3-2x^2-2x+1=0,then A^2+B^2+C^2=?
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Step-by-step explanation:
According to my view ,
A + B + C = 2/1 = 2
AB + BC + CA = -2
A² + B² + C² = (A+B+C)² - 2(AB+BC+CA)
= (2)² - 2(-2)
= 4 + 4 = 8
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