Question

A. B. C are three cups having capacities of 120.180 and 200 cc respectively which are completely filled with
tea of three different varieties. They are all mixed in a separate vessel of capacity more than that of A. B. C
take Tether, and then the mixture is poured successively into A. B. C. Then how much (in cc) of A and B's
there in c​

Answer 1

Explanation:

Ratio of milk and water

=(61×5+83×4+125×5):(65×5+85×4+127×5)

=(65+23+1225):(625+25+1235)

=(1210+18+25):(1250+30+35)

=1253:12115

Answer 2

ratio of a b and c teas in mixture us 12:15:20

NOw after mixture poured into all 3 cups successively mix in cups I as capacity mentioned in question

so now capacity of c cup is 200 cc so 200 cc mixture is there

now a tea in that mixture is (12 x200) /50=48

same for b tea is (15x200)/50= 72

ans is 48 and 72