Question

A,B,C are three metals with atomic number 4,11,13 respectively. Arrange the metals in the increasing order of their valency.

Answer 1

Let's write their electronic configuration

A --- 2,2
B --- 2 , 8 , 1
C --- 2 , 8 , 3

Valency of A -- 2
Valency of B -- 1
Valency of C -- 3

Answer is B < A < C

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Answer 2

The metals in increasing order of their valency are B (Na) with valency 1, A (Be) with valency 2, and C (Al) with valency 3.

• The valency of an element is defined as the number of electrons it can lose or gain in chemical reactions. The valency of an element is directly related to its electron configuration, and can be determined from the number of valence electrons present in the outermost energy level of its atoms.

• The atomic number of the element A is 4, which corresponds to beryllium (Be). Beryllium has 2 valence electrons, and typically has a valency of 2.

• The atomic number of the element B is 11, which corresponds to sodium (Na). Sodium has 1 valence electron, and typically has a valence of 1.

• The atomic number of the element C is 13, which corresponds to aluminum (Al). Aluminum has 3 valence electrons, and typically has a valency of 3.

Therefore, tte metals in increasing order of their valency are: B (Na) with valency 1, A (Be) with valency 2, and C (Al) with valency 3.

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