Question

A,B,C are three points on the circle with centre o such that angle aob is 90 and angle aoc 110 find angle bac

Answer 1

Let the centre of the circle be O.

Given : AB and AC subtend 80° and 120° at centre.

⇒ ∠AOB = 80° and ∠BOC = 120°

 

Now ∠AOB + ∠BOC + ∠AOC = 360°

⇒ 80° + 120° + ∠AOC = 360°

⇒ ∠AOC = 360° – 200° = 160°

 

We know that angle subtended by the arc at the centre is double the angle subtended by it at any point on the circle.

 

Hence In ∆ABC

∠A = 60°,  ∠B = 80°  and ∠C = 40°

Answer 2

hence the answer is

angle BAC is 60*