a(b-c)+b(c-a)+c(a-b)=0 it forms an AP
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Answered by
2
Answer:
Step-by-step explanation:
a(b-c)+b(c-a)+c(a-b)
⇒ab-ac+bc-ab+ac_bc
⇒0
Answered by
1
Answer:
It doesnot form an A.P.
Given : a(b-c)+b(c-a)+c(a-b)=0
Let Ist term =a(b-c), IInd term =b(c-a), IIIrd term = c(a-b)
For an A.P, IInd term - Ist term = IIIrd term - IInd term
b(c-a)-a(b-c)= bc-ab-ab+ac = bc-2ab+ac ...........(1)
c(a-b)-b(c-a) = ac-bc-bc+ab = ac-2bc+ab ............(2)
(1)≠(2)
Hence,it doesnot form an A.P.
Step-by-step explanation:
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