Math, asked by rakxhitharamesh, 9 months ago

a(b-c)+b(c-a)+c(a-b)=0 it forms an AP​

Answers

Answered by vihansonu
2

Answer:

Step-by-step explanation:

a(b-c)+b(c-a)+c(a-b)

⇒ab-ac+bc-ab+ac_bc

⇒0

Answered by aishwaryar1807
1

Answer:

It doesnot form an A.P.

Given : a(b-c)+b(c-a)+c(a-b)=0

Let Ist term =a(b-c), IInd term =b(c-a), IIIrd term = c(a-b)

For an A.P, IInd term - Ist term = IIIrd term - IInd term

        b(c-a)-a(b-c)= bc-ab-ab+ac = bc-2ab+ac    ...........(1)

        c(a-b)-b(c-a) = ac-bc-bc+ab = ac-2bc+ab    ............(2)

                                (1)≠(2)

                      Hence,it doesnot form an A.P.

Step-by-step explanation:

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