Question

a (b-c) +b(c-a)+c(a-b)​

Answer 1

a(b-c) +b(c-a)+c(a-b)

ab-ac + bc-ab + ac-bc

= 0

Answer 2

Answer:

a(b - c)+b(c - a)+c(a - b)

=ab - ac + bc - ab +ac -bc

all of them will cancel out and you will obtain 0 as your answer

so answer is 0

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