ABC is a triangle with AB=AC,D and E are points on the sides AB and AC respectively,such that AD=AE.show thatB,C,D andE are concyclic
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Step-by-step explanation:
Given:
AD = AE …(i)
AB = AC …(ii)
Subtracting AD from both sides, we get:
⟹ AB – AD = AC – AD
⟹ AB – AD = AC - AE (Since, AD = AE)
⟹ BD = EC …(iii)
Dividing equation (i) by equation (iii), we get:
AD/DB = AE/EC
Applying the converse of Thales’ theorem, DE‖BC
⟹ ∠DEC + ∠ECB = 1800 (Sum of interior angles on the same side of a Transvesal Line is 00 .)
⟹ ∠DEC + ∠CBD = 1800 (Since, AB = AC ⟹ ∠B = ∠C)
Hence, quadrilateral BCED is cyclic.
Therefore, B,C,E and D are concylic points.
Adithi03:
thank u
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