a[b-c] + b[c-a] + c [ a-b]
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Answered by
3
a[b-c]+b[c-a]+c[a-b]
=ab-ac+bc-ab+ac-bc
=ab-ab-ac+ac+bc-bc
=0
Answered by
0
Answer:
0
Step-by-step explanation:
a(b-c)+b(c-a)c(a-b)
ab-ac+bc-ba+ca-cb
0
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