a(b-c)+b(c-a)+c(a-b)
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Answer:
see the attachment
Step-by-step explanation:
hope it helps
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Step-by-step explanation:
a(b-c)+b(c-a)+c(a-b)
=ab-ac+bc-ab+ac-bc
=ab-ab+bc-bc+ac-ac
=0+0+0
=0
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