Math, asked by diya9291, 9 months ago

a(b-c)-b(c-a)-c(a-b)

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Answers

Answered by amankumaraman11
0

  \tt{}a(b-c)-b(c-a)-c(a-b) \\  \tt{}ab - ac - bc + ba - ca + cb

  • Rearranging the terms,

\tt{}ab + ba- ac- ca - bc   + cb  \\ \to \:  \tt \green{ 2ab - 2ac - 2bc} \\ \to \:  \tt \pink{ 2(ab - ac - bc)}

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